Search a number
-
+
653472000012133 is a prime number
BaseRepresentation
bin1001010010010101000100111…
…0011011100110111101100101
310011200202022110020121200001001
42110211101032123212331211
51141122441124000342013
610233452520435433301
7254433536225111251
oct22445211633467545
93150668406550031
10653472000012133
1117a241a12032965
126135b302755831
13220821b6c951b3
14b7522dc007261
15508348de41ddd
hex252544e6e6f65

653472000012133 has 2 divisors, whose sum is σ = 653472000012134. Its totient is φ = 653472000012132.

The previous prime is 653472000012079. The next prime is 653472000012179. The reversal of 653472000012133 is 331210000274356.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 420600951239364 + 232871048772769 = 20508558^2 + 15260113^2 .

It is a cyclic number.

It is not a de Polignac number, because 653472000012133 - 249 = 90522046590821 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 653472000012092 and 653472000012101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (653472000019133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 326736000006066 + 326736000006067.

It is an arithmetic number, because the mean of its divisors is an integer number (326736000006067).

Almost surely, 2653472000012133 is an apocalyptic number.

It is an amenable number.

653472000012133 is a deficient number, since it is larger than the sum of its proper divisors (1).

653472000012133 is an equidigital number, since it uses as much as digits as its factorization.

653472000012133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 90720, while the sum is 37.

Adding to 653472000012133 its reverse (331210000274356), we get a palindrome (984682000286489).

The spelling of 653472000012133 in words is "six hundred fifty-three trillion, four hundred seventy-two billion, twelve thousand, one hundred thirty-three".