Base | Representation |
---|---|
bin | 111100111000111111… |
… | …101111110011110001 |
3 | 20020202111101221111002 |
4 | 330320333233303301 |
5 | 2032344432310213 |
6 | 50011400131345 |
7 | 4503124105154 |
oct | 747077576361 |
9 | 206674357432 |
10 | 65380744433 |
11 | 258007a8a94 |
12 | 10807a66b55 |
13 | 621c447a34 |
14 | 3243345c9b |
15 | 1a79d17658 |
hex | f38fefcf1 |
65380744433 has 2 divisors, whose sum is σ = 65380744434. Its totient is φ = 65380744432.
The previous prime is 65380744417. The next prime is 65380744459. The reversal of 65380744433 is 33444708356.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 57990419344 + 7390325089 = 240812^2 + 85967^2 .
It is a cyclic number.
It is not a de Polignac number, because 65380744433 - 24 = 65380744417 is a prime.
It is a super-2 number, since 2×653807444332 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (65380744493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32690372216 + 32690372217.
It is an arithmetic number, because the mean of its divisors is an integer number (32690372217).
Almost surely, 265380744433 is an apocalyptic number.
It is an amenable number.
65380744433 is a deficient number, since it is larger than the sum of its proper divisors (1).
65380744433 is an equidigital number, since it uses as much as digits as its factorization.
65380744433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2903040, while the sum is 47.
The spelling of 65380744433 in words is "sixty-five billion, three hundred eighty million, seven hundred forty-four thousand, four hundred thirty-three".
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