Search a number
-
+
65441143255093 is a prime number
BaseRepresentation
bin11101110000100101101000…
…00110001111000000110101
322120201010000210100221000221
432320102310012033000311
532034141430133130333
6351103125101534341
716532652351461614
oct1670226406170065
9276633023327027
1065441143255093
1119940484358521
12740ab225743b1
132a690c514a338
14122352260b87b
1578741ac31d2d
hex3b84b418f035

65441143255093 has 2 divisors, whose sum is σ = 65441143255094. Its totient is φ = 65441143255092.

The previous prime is 65441143255087. The next prime is 65441143255129. The reversal of 65441143255093 is 39055234114456.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 47057432264964 + 18383710990129 = 6859842^2 + 4287623^2 .

It is a cyclic number.

It is not a de Polignac number, because 65441143255093 - 233 = 65432553320501 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 65441143255093.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (65441143255693) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32720571627546 + 32720571627547.

It is an arithmetic number, because the mean of its divisors is an integer number (32720571627547).

Almost surely, 265441143255093 is an apocalyptic number.

It is an amenable number.

65441143255093 is a deficient number, since it is larger than the sum of its proper divisors (1).

65441143255093 is an equidigital number, since it uses as much as digits as its factorization.

65441143255093 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7776000, while the sum is 52.

The spelling of 65441143255093 in words is "sixty-five trillion, four hundred forty-one billion, one hundred forty-three million, two hundred fifty-five thousand, ninety-three".