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6550364231197 is a prime number
BaseRepresentation
bin101111101010010000000…
…1000100001011000011101
3212012012122010221022000221
41133110200020201120131
51324310121220344242
621533110142321341
71244151063202033
oct137244010413035
925165563838027
106550364231197
1120a5aa2928216
12899607889251
133869098471b7
14189079c76553
15b55cb40b167
hex5f52022161d

6550364231197 has 2 divisors, whose sum is σ = 6550364231198. Its totient is φ = 6550364231196.

The previous prime is 6550364231183. The next prime is 6550364231237. The reversal of 6550364231197 is 7911324630556.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3959507002201 + 2590857228996 = 1989851^2 + 1609614^2 .

It is a cyclic number.

It is not a de Polignac number, because 6550364231197 - 215 = 6550364198429 is a prime.

It is a super-2 number, since 2×65503642311972 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (6550364231497) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3275182115598 + 3275182115599.

It is an arithmetic number, because the mean of its divisors is an integer number (3275182115599).

Almost surely, 26550364231197 is an apocalyptic number.

It is an amenable number.

6550364231197 is a deficient number, since it is larger than the sum of its proper divisors (1).

6550364231197 is an equidigital number, since it uses as much as digits as its factorization.

6550364231197 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4082400, while the sum is 52.

The spelling of 6550364231197 in words is "six trillion, five hundred fifty billion, three hundred sixty-four million, two hundred thirty-one thousand, one hundred ninety-seven".