Base | Representation |
---|---|
bin | 101111101010010000000… |
… | …1000100001011000101011 |
3 | 212012012122010221022001110 |
4 | 1133110200020201120223 |
5 | 1324310121220344321 |
6 | 21533110142321403 |
7 | 1244151063202053 |
oct | 137244010413053 |
9 | 25165563838043 |
10 | 6550364231211 |
11 | 20a5aa2928229 |
12 | 899607889263 |
13 | 3869098471c8 |
14 | 189079c76563 |
15 | b55cb40b176 |
hex | 5f52022162b |
6550364231211 has 32 divisors (see below), whose sum is σ = 9269075495680. Its totient is φ = 4103182915200.
The previous prime is 6550364231197. The next prime is 6550364231237. The reversal of 6550364231211 is 1121324630556.
It is a happy number.
It is not a de Polignac number, because 6550364231211 - 217 = 6550364100139 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 6550364231211.
It is not an unprimeable number, because it can be changed into a prime (6550364231261) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2997156 + ... + 4699326.
It is an arithmetic number, because the mean of its divisors is an integer number (289658609240).
Almost surely, 26550364231211 is an apocalyptic number.
6550364231211 is a deficient number, since it is larger than the sum of its proper divisors (2718711264469).
6550364231211 is a wasteful number, since it uses less digits than its factorization.
6550364231211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1702747.
The product of its (nonzero) digits is 129600, while the sum is 39.
Adding to 6550364231211 its reverse (1121324630556), we get a palindrome (7671688861767).
The spelling of 6550364231211 in words is "six trillion, five hundred fifty billion, three hundred sixty-four million, two hundred thirty-one thousand, two hundred eleven".
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