Base | Representation |
---|---|
bin | 111101001000100010… |
… | …000101101001100111 |
3 | 20021102122212212121022 |
4 | 331020202011221213 |
5 | 2033413144430111 |
6 | 50053311041355 |
7 | 4512440510456 |
oct | 751042055147 |
9 | 207378785538 |
10 | 65641405031 |
11 | 25924953174 |
12 | 1087b21025b |
13 | 6261450887 |
14 | 3269bd8b9d |
15 | 1a92b552db |
hex | f48885a67 |
65641405031 has 2 divisors, whose sum is σ = 65641405032. Its totient is φ = 65641405030.
The previous prime is 65641404977. The next prime is 65641405043. The reversal of 65641405031 is 13050414656.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-65641405031 is a prime.
It is a super-2 number, since 2×656414050312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 65641404982 and 65641405000.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (65641405831) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32820702515 + 32820702516.
It is an arithmetic number, because the mean of its divisors is an integer number (32820702516).
Almost surely, 265641405031 is an apocalyptic number.
65641405031 is a deficient number, since it is larger than the sum of its proper divisors (1).
65641405031 is an equidigital number, since it uses as much as digits as its factorization.
65641405031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 43200, while the sum is 35.
Adding to 65641405031 its reverse (13050414656), we get a palindrome (78691819687).
The spelling of 65641405031 in words is "sixty-five billion, six hundred forty-one million, four hundred five thousand, thirty-one".
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