Base | Representation |
---|---|
bin | 111101010111001100… |
… | …011011000010001010 |
3 | 20022001210201212220000 |
4 | 331113030123002022 |
5 | 2034414132234230 |
6 | 50133535143430 |
7 | 4521515343432 |
oct | 752714330212 |
9 | 208053655800 |
10 | 65887383690 |
11 | 25a4078a617 |
12 | 10929674b76 |
13 | 62a03b5a8b |
14 | 32907492c2 |
15 | 1aa9542b60 |
hex | f5731b08a |
65887383690 has 160 divisors (see below), whose sum is σ = 179331379920. Its totient is φ = 17356032000.
The previous prime is 65887383673. The next prime is 65887383733. The reversal of 65887383690 is 9638378856.
65887383690 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 8 ways, for example, as 32728066281 + 33159317409 = 180909^2 + 182097^2 .
It is a super-2 number, since 2×658873836902 (a number of 22 digits) contains 22 as substring.
It is a Curzon number.
It is an unprimeable number.
It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 35403360 + ... + 35405220.
Almost surely, 265887383690 is an apocalyptic number.
It is a practical number, because each smaller number is the sum of distinct divisors of 65887383690, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (89665689960).
65887383690 is an abundant number, since it is smaller than the sum of its proper divisors (113443996230).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
65887383690 is a wasteful number, since it uses less digits than its factorization.
65887383690 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2390 (or 2381 counting only the distinct ones).
The product of its (nonzero) digits is 52254720, while the sum is 63.
The spelling of 65887383690 in words is "sixty-five billion, eight hundred eighty-seven million, three hundred eighty-three thousand, six hundred ninety".
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