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660105024881 is a prime number
BaseRepresentation
bin10011001101100010101…
…00110101010101110001
32100002211212001200021212
421212301110311111301
541303343341244011
61223125325325505
765456006063501
oct11466124652561
92302755050255
10660105024881
11234a49094385
12a7b23a06895
134a32b09a3a3
1423d40a75a01
151228691908b
hex99b1535571

660105024881 has 2 divisors, whose sum is σ = 660105024882. Its totient is φ = 660105024880.

The previous prime is 660105024869. The next prime is 660105024883. The reversal of 660105024881 is 188420501066.

660105024881 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 483045850225 + 177059174656 = 695015^2 + 420784^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-660105024881 is a prime.

It is a super-2 number, since 2×6601050248812 (a number of 24 digits) contains 22 as substring.

Together with 660105024883, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (660105024883) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 330052512440 + 330052512441.

It is an arithmetic number, because the mean of its divisors is an integer number (330052512441).

Almost surely, 2660105024881 is an apocalyptic number.

It is an amenable number.

660105024881 is a deficient number, since it is larger than the sum of its proper divisors (1).

660105024881 is an equidigital number, since it uses as much as digits as its factorization.

660105024881 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 92160, while the sum is 41.

The spelling of 660105024881 in words is "six hundred sixty billion, one hundred five million, twenty-four thousand, eight hundred eighty-one".