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660136412114149 is a prime number
BaseRepresentation
bin1001011000011000111111110…
…0010110001110110011100101
310012120100102110120202002022111
42112012033330112032303211
51143011133333000123044
610255554251532001021
7256022165454236365
oct22606177426166345
93176312416662274
10660136412114149
11181381309a10473
1262056a38900171
132244679a81bc09
14b902ab68b89a5
15514b9e29c4b34
hex25863fc58ece5

660136412114149 has 2 divisors, whose sum is σ = 660136412114150. Its totient is φ = 660136412114148.

The previous prime is 660136412114077. The next prime is 660136412114203. The reversal of 660136412114149 is 941411214631066.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 529546713181924 + 130589698932225 = 23011882^2 + 11427585^2 .

It is a cyclic number.

It is not a de Polignac number, because 660136412114149 - 223 = 660136403725541 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (660136412174149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 330068206057074 + 330068206057075.

It is an arithmetic number, because the mean of its divisors is an integer number (330068206057075).

Almost surely, 2660136412114149 is an apocalyptic number.

It is an amenable number.

660136412114149 is a deficient number, since it is larger than the sum of its proper divisors (1).

660136412114149 is an equidigital number, since it uses as much as digits as its factorization.

660136412114149 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 746496, while the sum is 49.

The spelling of 660136412114149 in words is "six hundred sixty trillion, one hundred thirty-six billion, four hundred twelve million, one hundred fourteen thousand, one hundred forty-nine".