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66323714481383 is a prime number
BaseRepresentation
bin11110001010010001100010…
…11100010001110011100111
322200211111002200211120101212
433011020301130101303213
532143121431401401013
6353020405510142035
716653505321226042
oct1705106134216347
9280744080746355
1066323714481383
111a1508028506a7
127531b9195191b
132b013b7b38998
141254128dbdc59
157a03730dc6a8
hex3c5231711ce7

66323714481383 has 2 divisors, whose sum is σ = 66323714481384. Its totient is φ = 66323714481382.

The previous prime is 66323714481379. The next prime is 66323714481491. The reversal of 66323714481383 is 38318441732366.

66323714481383 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 66323714481383 - 22 = 66323714481379 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (66323714481083) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33161857240691 + 33161857240692.

It is an arithmetic number, because the mean of its divisors is an integer number (33161857240692).

Almost surely, 266323714481383 is an apocalyptic number.

66323714481383 is a deficient number, since it is larger than the sum of its proper divisors (1).

66323714481383 is an equidigital number, since it uses as much as digits as its factorization.

66323714481383 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 41803776, while the sum is 59.

The spelling of 66323714481383 in words is "sixty-six trillion, three hundred twenty-three billion, seven hundred fourteen million, four hundred eighty-one thousand, three hundred eighty-three".