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665133250505653 is a prime number
BaseRepresentation
bin1001011100111011110110011…
…1000111111110101110110101
310020020001010011211201212012201
42113032331213013332232311
51144140020344112140103
610314341555204144501
7260046201666620206
oct22716754707765665
93206033154655181
10665133250505653
11182a28477a16746
1262723343998131
1322719a47897007
14ba3689a3cb5ad
1551d699787d51d
hex25cef671febb5

665133250505653 has 2 divisors, whose sum is σ = 665133250505654. Its totient is φ = 665133250505652.

The previous prime is 665133250505617. The next prime is 665133250505681. The reversal of 665133250505653 is 356505052331566.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 520286200507089 + 144847049998564 = 22809783^2 + 12035242^2 .

It is a cyclic number.

It is not a de Polignac number, because 665133250505653 - 221 = 665133248408501 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 665133250505594 and 665133250505603.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (665133250505683) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 332566625252826 + 332566625252827.

It is an arithmetic number, because the mean of its divisors is an integer number (332566625252827).

Almost surely, 2665133250505653 is an apocalyptic number.

It is an amenable number.

665133250505653 is a deficient number, since it is larger than the sum of its proper divisors (1).

665133250505653 is an equidigital number, since it uses as much as digits as its factorization.

665133250505653 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36450000, while the sum is 55.

The spelling of 665133250505653 in words is "six hundred sixty-five trillion, one hundred thirty-three billion, two hundred fifty million, five hundred five thousand, six hundred fifty-three".