Base | Representation |
---|---|
bin | 11110010100010110100011… |
… | …01010110110100001101111 |
3 | 22202001120220221012121011111 |
4 | 33022023101222312201233 |
5 | 32214310130002240142 |
6 | 353443435235332451 |
7 | 20020514516012215 |
oct | 1712132152664157 |
9 | 282046827177144 |
10 | 66670000040047 |
11 | 1a274651a37218 |
12 | 7589114151127 |
13 | 2b27c52cc8411 |
14 | 1266bb93d2cb5 |
15 | 7a938dec5e17 |
hex | 3ca2d1ab686f |
66670000040047 has 2 divisors, whose sum is σ = 66670000040048. Its totient is φ = 66670000040046.
The previous prime is 66670000039969. The next prime is 66670000040071. The reversal of 66670000040047 is 74004000007666.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 66670000040047 - 215 = 66670000007279 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 66670000039991 and 66670000040009.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (66670000040087) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33335000020023 + 33335000020024.
It is an arithmetic number, because the mean of its divisors is an integer number (33335000020024).
Almost surely, 266670000040047 is an apocalyptic number.
66670000040047 is a deficient number, since it is larger than the sum of its proper divisors (1).
66670000040047 is an equidigital number, since it uses as much as digits as its factorization.
66670000040047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 169344, while the sum is 40.
The spelling of 66670000040047 in words is "sixty-six trillion, six hundred seventy billion, forty thousand, forty-seven".
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