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667151413169 is a prime number
BaseRepresentation
bin10011011010101010101…
…00101010111110110001
32100210000221002021211212
421231111110222332301
541412311230210134
61230252442045505
766125430305543
oct11552524527661
92323027067755
10667151413169
11237a3464217a
12a936b7a9895
134abb1b95807
142440c829693
151254a347bce
hex9b5552afb1

667151413169 has 2 divisors, whose sum is σ = 667151413170. Its totient is φ = 667151413168.

The previous prime is 667151413151. The next prime is 667151413171. The reversal of 667151413169 is 961314151766.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 613425736225 + 53725676944 = 783215^2 + 231788^2 .

It is a cyclic number.

It is not a de Polignac number, because 667151413169 - 28 = 667151412913 is a prime.

It is a super-2 number, since 2×6671514131692 (a number of 24 digits) contains 22 as substring.

Together with 667151413171, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (667151413469) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 333575706584 + 333575706585.

It is an arithmetic number, because the mean of its divisors is an integer number (333575706585).

Almost surely, 2667151413169 is an apocalyptic number.

It is an amenable number.

667151413169 is a deficient number, since it is larger than the sum of its proper divisors (1).

667151413169 is an equidigital number, since it uses as much as digits as its factorization.

667151413169 is an evil number, because the sum of its binary digits is even.

The product of its digits is 816480, while the sum is 50.

The spelling of 667151413169 in words is "six hundred sixty-seven billion, one hundred fifty-one million, four hundred thirteen thousand, one hundred sixty-nine".