Base | Representation |
---|---|
bin | 111110010110110001… |
… | …100100101101010101 |
3 | 20101211010221001002101 |
4 | 332112301210231111 |
5 | 2044110221243003 |
6 | 50431442242101 |
7 | 4560120231364 |
oct | 762661445525 |
9 | 211733831071 |
10 | 66954087253 |
11 | 26438922809 |
12 | 10b86956331 |
13 | 64103a9211 |
14 | 335229b7db |
15 | 1b1ceed11d |
hex | f96c64b55 |
66954087253 has 2 divisors, whose sum is σ = 66954087254. Its totient is φ = 66954087252.
The previous prime is 66954087247. The next prime is 66954087287. The reversal of 66954087253 is 35278045966.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 48939615729 + 18014471524 = 221223^2 + 134218^2 .
It is a cyclic number.
It is not a de Polignac number, because 66954087253 - 29 = 66954086741 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 66954087194 and 66954087203.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (66954087353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33477043626 + 33477043627.
It is an arithmetic number, because the mean of its divisors is an integer number (33477043627).
Almost surely, 266954087253 is an apocalyptic number.
It is an amenable number.
66954087253 is a deficient number, since it is larger than the sum of its proper divisors (1).
66954087253 is an equidigital number, since it uses as much as digits as its factorization.
66954087253 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10886400, while the sum is 55.
The spelling of 66954087253 in words is "sixty-six billion, nine hundred fifty-four million, eighty-seven thousand, two hundred fifty-three".
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