Base | Representation |
---|---|
bin | 111110010111010001… |
… | …011000110000010011 |
3 | 20101211201121201221011 |
4 | 332113101120300103 |
5 | 2044114340130044 |
6 | 50432341111351 |
7 | 4560251144254 |
oct | 762721306023 |
9 | 211751551834 |
10 | 66962426899 |
11 | 264425a9485 |
12 | 10b896b8557 |
13 | 6412039114 |
14 | 335342cb2b |
15 | 1b1dae9134 |
hex | f97458c13 |
66962426899 has 2 divisors, whose sum is σ = 66962426900. Its totient is φ = 66962426898.
The previous prime is 66962426893. The next prime is 66962426911. The reversal of 66962426899 is 99862426966.
66962426899 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 66962426899 - 29 = 66962426387 is a prime.
It is a super-3 number, since 3×669624268993 (a number of 33 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (66962426893) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33481213449 + 33481213450.
It is an arithmetic number, because the mean of its divisors is an integer number (33481213450).
Almost surely, 266962426899 is an apocalyptic number.
66962426899 is a deficient number, since it is larger than the sum of its proper divisors (1).
66962426899 is an equidigital number, since it uses as much as digits as its factorization.
66962426899 is an evil number, because the sum of its binary digits is even.
The product of its digits is 120932352, while the sum is 67.
Adding to 66962426899 its sum of digits (67), we get a palindrome (66962426966).
The spelling of 66962426899 in words is "sixty-six billion, nine hundred sixty-two million, four hundred twenty-six thousand, eight hundred ninety-nine".
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