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67122113437 is a prime number
BaseRepresentation
bin111110100000110010…
…100010101110011101
320102020212002122200101
4332200302202232131
52044431230112222
650500243501101
74564230356551
oct764062425635
9212225078611
1067122113437
1126514757325
1211013087791
136439149cb2
14336a719861
151b2cb3d927
hexfa0ca2b9d

67122113437 has 2 divisors, whose sum is σ = 67122113438. Its totient is φ = 67122113436.

The previous prime is 67122113419. The next prime is 67122113459. The reversal of 67122113437 is 73431122176.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 38380336281 + 28741777156 = 195909^2 + 169534^2 .

It is a cyclic number.

It is not a de Polignac number, because 67122113437 - 235 = 32762375069 is a prime.

It is a super-3 number, since 3×671221134373 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 67122113396 and 67122113405.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (67122113137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33561056718 + 33561056719.

It is an arithmetic number, because the mean of its divisors is an integer number (33561056719).

Almost surely, 267122113437 is an apocalyptic number.

It is an amenable number.

67122113437 is a deficient number, since it is larger than the sum of its proper divisors (1).

67122113437 is an equidigital number, since it uses as much as digits as its factorization.

67122113437 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 42336, while the sum is 37.

The spelling of 67122113437 in words is "sixty-seven billion, one hundred twenty-two million, one hundred thirteen thousand, four hundred thirty-seven".