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671276316253 is a prime number
BaseRepresentation
bin10011100010010110010…
…11111011011001011101
32101011200101211002010011
421301023023323121131
541444233214110003
61232214033043221
766332565354214
oct11611313733135
92334611732104
10671276316253
11239760a86994
12aa1210b6511
134b3bb639a7a
14246c05b407b
15126dc54146d
hex9c4b2fb65d

671276316253 has 2 divisors, whose sum is σ = 671276316254. Its totient is φ = 671276316252.

The previous prime is 671276316241. The next prime is 671276316257. The reversal of 671276316253 is 352613672176.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 560165427364 + 111110888889 = 748442^2 + 333333^2 .

It is a cyclic number.

It is not a de Polignac number, because 671276316253 - 221 = 671274219101 is a prime.

It is a super-2 number, since 2×6712763162532 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 671276316197 and 671276316206.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (671276316257) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 335638158126 + 335638158127.

It is an arithmetic number, because the mean of its divisors is an integer number (335638158127).

Almost surely, 2671276316253 is an apocalyptic number.

It is an amenable number.

671276316253 is a deficient number, since it is larger than the sum of its proper divisors (1).

671276316253 is an equidigital number, since it uses as much as digits as its factorization.

671276316253 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1905120, while the sum is 49.

The spelling of 671276316253 in words is "six hundred seventy-one billion, two hundred seventy-six million, three hundred sixteen thousand, two hundred fifty-three".