Base | Representation |
---|---|
bin | 111110100110011000… |
… | …011101111001011101 |
3 | 20102111101122121012012 |
4 | 332212120131321131 |
5 | 2100124240104323 |
6 | 50513434521005 |
7 | 4566450034121 |
oct | 764630357135 |
9 | 212441577165 |
10 | 67215941213 |
11 | 26562712543 |
12 | 1103a596165 |
13 | 645270c2a5 |
14 | 3378d81581 |
15 | 1b35ec4678 |
hex | fa661de5d |
67215941213 has 2 divisors, whose sum is σ = 67215941214. Its totient is φ = 67215941212.
The previous prime is 67215941173. The next prime is 67215941281. The reversal of 67215941213 is 31214951276.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 67041119929 + 174821284 = 258923^2 + 13222^2 .
It is a cyclic number.
It is not a de Polignac number, because 67215941213 - 234 = 50036072029 is a prime.
It is a super-2 number, since 2×672159412132 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (67215947213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33607970606 + 33607970607.
It is an arithmetic number, because the mean of its divisors is an integer number (33607970607).
Almost surely, 267215941213 is an apocalyptic number.
It is an amenable number.
67215941213 is a deficient number, since it is larger than the sum of its proper divisors (1).
67215941213 is an equidigital number, since it uses as much as digits as its factorization.
67215941213 is an evil number, because the sum of its binary digits is even.
The product of its digits is 90720, while the sum is 41.
The spelling of 67215941213 in words is "sixty-seven billion, two hundred fifteen million, nine hundred forty-one thousand, two hundred thirteen".
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