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673128443831 is a prime number
BaseRepresentation
bin10011100101110011001…
…01001110111110110111
32101100110110220220111212
421302321211032332313
542012031340200311
61233121514352035
766426515240114
oct11627145167667
92340413826455
10673128443831
1123a521504838
12aa55942b61b
134b62527b74c
142481857990b
1512799e44c8b
hex9cb994efb7

673128443831 has 2 divisors, whose sum is σ = 673128443832. Its totient is φ = 673128443830.

The previous prime is 673128443759. The next prime is 673128443837. The reversal of 673128443831 is 138344821376.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 673128443831 - 222 = 673124249527 is a prime.

It is a super-3 number, since 3×6731284438313 (a number of 36 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 673128443831.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (673128443837) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 336564221915 + 336564221916.

It is an arithmetic number, because the mean of its divisors is an integer number (336564221916).

Almost surely, 2673128443831 is an apocalyptic number.

673128443831 is a deficient number, since it is larger than the sum of its proper divisors (1).

673128443831 is an equidigital number, since it uses as much as digits as its factorization.

673128443831 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2322432, while the sum is 50.

The spelling of 673128443831 in words is "six hundred seventy-three billion, one hundred twenty-eight million, four hundred forty-three thousand, eight hundred thirty-one".