Base | Representation |
---|---|
bin | 111110101100001011… |
… | …000111110001100001 |
3 | 20102202011111002020122 |
4 | 332230023013301201 |
5 | 2100324123343032 |
6 | 50531225250025 |
7 | 4602036650333 |
oct | 765413076141 |
9 | 212664432218 |
10 | 67313106017 |
11 | 26602547933 |
12 | 11067033915 |
13 | 646989c461 |
14 | 3387c35453 |
15 | 1b3e7b9012 |
hex | fac2c7c61 |
67313106017 has 2 divisors, whose sum is σ = 67313106018. Its totient is φ = 67313106016.
The previous prime is 67313106013. The next prime is 67313106019. The reversal of 67313106017 is 71060131376.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 56097448801 + 11215657216 = 236849^2 + 105904^2 .
It is a cyclic number.
It is not a de Polignac number, because 67313106017 - 22 = 67313106013 is a prime.
Together with 67313106019, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (67313106013) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33656553008 + 33656553009.
It is an arithmetic number, because the mean of its divisors is an integer number (33656553009).
Almost surely, 267313106017 is an apocalyptic number.
It is an amenable number.
67313106017 is a deficient number, since it is larger than the sum of its proper divisors (1).
67313106017 is an equidigital number, since it uses as much as digits as its factorization.
67313106017 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15876, while the sum is 35.
The spelling of 67313106017 in words is "sixty-seven billion, three hundred thirteen million, one hundred six thousand, seventeen".
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