Base | Representation |
---|---|
bin | 1001100100001110000101010… |
… | …1100101110011110011111111 |
3 | 10021021101211220221212122200021 |
4 | 2121003201111211303303333 |
5 | 1201212234002001424044 |
6 | 10343353354001313011 |
7 | 261533660542103206 |
oct | 23103412545636377 |
9 | 3237354827778607 |
10 | 673143070342399 |
11 | 18553641144a638 |
12 | 635b7778335767 |
13 | 22b7b171a48357 |
14 | bc32426cd223d |
15 | 52c4ee1964e84 |
hex | 2643855973cff |
673143070342399 has 2 divisors, whose sum is σ = 673143070342400. Its totient is φ = 673143070342398.
The previous prime is 673143070342283. The next prime is 673143070342411. The reversal of 673143070342399 is 993243070341376.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 673143070342399 - 237 = 673005631388927 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (673143070342499) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 336571535171199 + 336571535171200.
It is an arithmetic number, because the mean of its divisors is an integer number (336571535171200).
Almost surely, 2673143070342399 is an apocalyptic number.
673143070342399 is a deficient number, since it is larger than the sum of its proper divisors (1).
673143070342399 is an equidigital number, since it uses as much as digits as its factorization.
673143070342399 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 61725888, while the sum is 61.
The spelling of 673143070342399 in words is "six hundred seventy-three trillion, one hundred forty-three billion, seventy million, three hundred forty-two thousand, three hundred ninety-nine".
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