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68042113 is a prime number
BaseRepresentation
bin1000000111000…
…11110110000001
311202000220020021
410003203312001
5114404321423
610430213441
71454230336
oct403436601
9152026207
1068042113
1135454057
121a954281
1311134609
14907298d
155e9095d
hex40e3d81

68042113 has 2 divisors, whose sum is σ = 68042114. Its totient is φ = 68042112.

The previous prime is 68042099. The next prime is 68042123. The reversal of 68042113 is 31124086.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 66129424 + 1912689 = 8132^2 + 1383^2 .

It is a cyclic number.

It is not a de Polignac number, because 68042113 - 29 = 68041601 is a prime.

It is not a weakly prime, because it can be changed into another prime (68042123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 34021056 + 34021057.

It is an arithmetic number, because the mean of its divisors is an integer number (34021057).

Almost surely, 268042113 is an apocalyptic number.

It is an amenable number.

68042113 is a deficient number, since it is larger than the sum of its proper divisors (1).

68042113 is an equidigital number, since it uses as much as digits as its factorization.

68042113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 25.

The square root of 68042113 is about 8248.7643317045. The cubic root of 68042113 is about 408.2497529707.

Adding to 68042113 its reverse (31124086), we get a palindrome (99166199).

The spelling of 68042113 in words is "sixty-eight million, forty-two thousand, one hundred thirteen".