Base | Representation |
---|---|
bin | 11110111101000001000100… |
… | …01010110000001111111111 |
3 | 22221000011101020120020021211 |
4 | 33132200202022300033333 |
5 | 32410203124011421143 |
6 | 400433351420105251 |
7 | 20223460016550322 |
oct | 1736404212601777 |
9 | 287004336506254 |
10 | 68067214951423 |
11 | 1a763164371176 |
12 | 7773a70695227 |
13 | 2bc99318c624c |
14 | 12b4683b7a7b9 |
15 | 7d08b789449d |
hex | 3de8222b03ff |
68067214951423 has 2 divisors, whose sum is σ = 68067214951424. Its totient is φ = 68067214951422.
The previous prime is 68067214951369. The next prime is 68067214951453. The reversal of 68067214951423 is 32415941276086.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 68067214951423 - 217 = 68067214820351 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (68067214951453) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 34033607475711 + 34033607475712.
It is an arithmetic number, because the mean of its divisors is an integer number (34033607475712).
It is a 1-persistent number, because it is pandigital, but 2⋅68067214951423 = 136134429902846 is not.
Almost surely, 268067214951423 is an apocalyptic number.
68067214951423 is a deficient number, since it is larger than the sum of its proper divisors (1).
68067214951423 is an equidigital number, since it uses as much as digits as its factorization.
68067214951423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17418240, while the sum is 58.
The spelling of 68067214951423 in words is "sixty-eight trillion, sixty-seven billion, two hundred fourteen million, nine hundred fifty-one thousand, four hundred twenty-three".
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