Base | Representation |
---|---|
bin | 1100101011111100… |
… | …11010110110101011 |
3 | 122120200100112021012 |
4 | 12111332122312223 |
5 | 102422122313103 |
6 | 3043510134135 |
7 | 330533460422 |
oct | 62576326653 |
9 | 18520315235 |
10 | 6811135403 |
11 | 2985787926 |
12 | 13a105134b |
13 | 84714a247 |
14 | 4888362b9 |
15 | 29ce5e2d8 |
hex | 195f9adab |
6811135403 has 2 divisors, whose sum is σ = 6811135404. Its totient is φ = 6811135402.
The previous prime is 6811135393. The next prime is 6811135421. The reversal of 6811135403 is 3045311186.
6811135403 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 6811135403 - 224 = 6794358187 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 6811135403.
It is not a weakly prime, because it can be changed into another prime (6811135423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3405567701 + 3405567702.
It is an arithmetic number, because the mean of its divisors is an integer number (3405567702).
Almost surely, 26811135403 is an apocalyptic number.
6811135403 is a deficient number, since it is larger than the sum of its proper divisors (1).
6811135403 is an equidigital number, since it uses as much as digits as its factorization.
6811135403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8640, while the sum is 32.
The square root of 6811135403 is about 82529.6031918244. The cubic root of 6811135403 is about 1895.5700489824.
Adding to 6811135403 its reverse (3045311186), we get a palindrome (9856446589).
The spelling of 6811135403 in words is "six billion, eight hundred eleven million, one hundred thirty-five thousand, four hundred three".
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