Base | Representation |
---|---|
bin | 110001100011110010110… |
… | …1100001110100111001011 |
3 | 220010011100120000121100122 |
4 | 1203013211230032213023 |
5 | 1343044144421201221 |
6 | 22253034150253455 |
7 | 1302051160005566 |
oct | 143074554164713 |
9 | 26104316017318 |
10 | 6811376740811 |
11 | 2196763663985 |
12 | 92011035728b |
13 | 3a54052c0666 |
14 | 19795b0934dd |
15 | bc2a5e35eab |
hex | 631e5b0e9cb |
6811376740811 has 2 divisors, whose sum is σ = 6811376740812. Its totient is φ = 6811376740810.
The previous prime is 6811376740801. The next prime is 6811376740829. The reversal of 6811376740811 is 1180476731186.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-6811376740811 is a prime.
It is a super-2 number, since 2×68113767408112 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (6811376740801) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3405688370405 + 3405688370406.
It is an arithmetic number, because the mean of its divisors is an integer number (3405688370406).
Almost surely, 26811376740811 is an apocalyptic number.
6811376740811 is a deficient number, since it is larger than the sum of its proper divisors (1).
6811376740811 is an equidigital number, since it uses as much as digits as its factorization.
6811376740811 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1354752, while the sum is 53.
The spelling of 6811376740811 in words is "six trillion, eight hundred eleven billion, three hundred seventy-six million, seven hundred forty thousand, eight hundred eleven".
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