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68149550101 is a prime number
BaseRepresentation
bin111111011110000001…
…111001110000010101
320111220110101211211011
4333132001321300111
52104032241100401
651150225212221
74631544421663
oct773601716025
9214813354734
1068149550101
11269a170a736
121125b191071
136570c72499
143426d69c33
151b8ce3e451
hexfde079c15

68149550101 has 2 divisors, whose sum is σ = 68149550102. Its totient is φ = 68149550100.

The previous prime is 68149550093. The next prime is 68149550159. The reversal of 68149550101 is 10105594186.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 68105340900 + 44209201 = 260970^2 + 6649^2 .

It is a cyclic number.

It is not a de Polignac number, because 68149550101 - 23 = 68149550093 is a prime.

It is a super-3 number, since 3×681495501013 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (68149550171) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 34074775050 + 34074775051.

It is an arithmetic number, because the mean of its divisors is an integer number (34074775051).

Almost surely, 268149550101 is an apocalyptic number.

It is an amenable number.

68149550101 is a deficient number, since it is larger than the sum of its proper divisors (1).

68149550101 is an equidigital number, since it uses as much as digits as its factorization.

68149550101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 43200, while the sum is 40.

The spelling of 68149550101 in words is "sixty-eight billion, one hundred forty-nine million, five hundred fifty thousand, one hundred one".