Base | Representation |
---|---|
bin | 111111011110000001… |
… | …111001110000010101 |
3 | 20111220110101211211011 |
4 | 333132001321300111 |
5 | 2104032241100401 |
6 | 51150225212221 |
7 | 4631544421663 |
oct | 773601716025 |
9 | 214813354734 |
10 | 68149550101 |
11 | 269a170a736 |
12 | 1125b191071 |
13 | 6570c72499 |
14 | 3426d69c33 |
15 | 1b8ce3e451 |
hex | fde079c15 |
68149550101 has 2 divisors, whose sum is σ = 68149550102. Its totient is φ = 68149550100.
The previous prime is 68149550093. The next prime is 68149550159. The reversal of 68149550101 is 10105594186.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 68105340900 + 44209201 = 260970^2 + 6649^2 .
It is a cyclic number.
It is not a de Polignac number, because 68149550101 - 23 = 68149550093 is a prime.
It is a super-3 number, since 3×681495501013 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (68149550171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 34074775050 + 34074775051.
It is an arithmetic number, because the mean of its divisors is an integer number (34074775051).
Almost surely, 268149550101 is an apocalyptic number.
It is an amenable number.
68149550101 is a deficient number, since it is larger than the sum of its proper divisors (1).
68149550101 is an equidigital number, since it uses as much as digits as its factorization.
68149550101 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 43200, while the sum is 40.
The spelling of 68149550101 in words is "sixty-eight billion, one hundred forty-nine million, five hundred fifty thousand, one hundred one".
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