Base | Representation |
---|---|
bin | 111111100100011111… |
… | …101010011100010101 |
3 | 20112012000111102200112 |
4 | 333210133222130111 |
5 | 2104243022434442 |
6 | 51205102052405 |
7 | 4634332361114 |
oct | 774437523425 |
9 | 215160442615 |
10 | 68258014997 |
11 | 26a47962a47 |
12 | 1128b57a105 |
13 | 658a58abb3 |
14 | 3437521c7b |
15 | 1b97717082 |
hex | fe47ea715 |
68258014997 has 2 divisors, whose sum is σ = 68258014998. Its totient is φ = 68258014996.
The previous prime is 68258014969. The next prime is 68258015051. The reversal of 68258014997 is 79941085286.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 64308395281 + 3949619716 = 253591^2 + 62846^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-68258014997 is a prime.
It is a super-2 number, since 2×682580149972 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (68258014397) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 34129007498 + 34129007499.
It is an arithmetic number, because the mean of its divisors is an integer number (34129007499).
Almost surely, 268258014997 is an apocalyptic number.
It is an amenable number.
68258014997 is a deficient number, since it is larger than the sum of its proper divisors (1).
68258014997 is an equidigital number, since it uses as much as digits as its factorization.
68258014997 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8709120, while the sum is 59.
The spelling of 68258014997 in words is "sixty-eight billion, two hundred fifty-eight million, fourteen thousand, nine hundred ninety-seven".
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