683724131 has 2 divisors, whose sum is σ = 683724132. Its totient is φ = 683724130.

The previous prime is 683724113. The next prime is 683724149. The reversal of 683724131 is 131427386.

Together with previous prime (683724113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a balanced prime because it is at equal distance from previous prime (683724113) and next prime (683724149).

It is a cyclic number.

It is not a de Polignac number, because 683724131 - 2¹⁰ = 683723107 is a prime.

It is a super-2 number, since 2×683724131² = 934957374623410322, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 683724091 and 683724100.

It is not a weakly prime, because it can be changed into another prime (683724161) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 341862065 + 341862066.

It is an arithmetic number, because the mean of its divisors is an integer number (341862066).

Almost surely, 2^683724131 is an apocalyptic number.

683724131 is a deficient number, since it is larger than the sum of its proper divisors (1).

683724131 is an equidigital number, since it uses as much as digits as its factorization.

683724131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 24192, while the sum is 35.

The square root of 683724131 is about 26148.1190719333. The cubic root of 683724131 is about 880.9683430591.

The spelling of 683724131 in words is "six hundred eighty-three million, seven hundred twenty-four thousand, one hundred thirty-one".