Base | Representation |
---|---|
bin | 110001110000111110101… |
… | …0101110000001001011111 |
3 | 220012212102210220022021112 |
4 | 1203201331111300021133 |
5 | 1344030141320230341 |
6 | 22314035514452235 |
7 | 1304102625313451 |
oct | 143417525601137 |
9 | 26185383808245 |
10 | 6839690789471 |
11 | 21a777315a7a1 |
12 | 9256b273407b |
13 | 3a7c982b77c7 |
14 | 1990856322d1 |
15 | bcdb1a33aeb |
hex | 6387d57025f |
6839690789471 has 2 divisors, whose sum is σ = 6839690789472. Its totient is φ = 6839690789470.
The previous prime is 6839690789441. The next prime is 6839690789483. The reversal of 6839690789471 is 1749870969386.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-6839690789471 is a prime.
It is a super-3 number, since 3×68396907894713 (a number of 39 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 6839690789392 and 6839690789401.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (6839690789441) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3419845394735 + 3419845394736.
It is an arithmetic number, because the mean of its divisors is an integer number (3419845394736).
Almost surely, 26839690789471 is an apocalyptic number.
6839690789471 is a deficient number, since it is larger than the sum of its proper divisors (1).
6839690789471 is an equidigital number, since it uses as much as digits as its factorization.
6839690789471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 987614208, while the sum is 77.
The spelling of 6839690789471 in words is "six trillion, eight hundred thirty-nine billion, six hundred ninety million, seven hundred eighty-nine thousand, four hundred seventy-one".
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