Search a number
-
+
6847612314161 is a prime number
BaseRepresentation
bin110001110100101010101…
…1111111110001000110001
3220020121212212122110021212
41203221111133332020301
51344142402223023121
622321425532325505
71304503134210563
oct143512537761061
926217785573255
106847612314161
1122000686a8513
12927143613895
133a895b4b2518
141995d770d333
15bd1c71cc25b
hex63a557fe231

6847612314161 has 2 divisors, whose sum is σ = 6847612314162. Its totient is φ = 6847612314160.

The previous prime is 6847612314133. The next prime is 6847612314163. The reversal of 6847612314161 is 1614132167486.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5803473721600 + 1044138592561 = 2409040^2 + 1021831^2 .

It is a cyclic number.

It is not a de Polignac number, because 6847612314161 - 26 = 6847612314097 is a prime.

It is a super-2 number, since 2×68476123141612 (a number of 26 digits) contains 22 as substring.

Together with 6847612314163, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (6847612314163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3423806157080 + 3423806157081.

It is an arithmetic number, because the mean of its divisors is an integer number (3423806157081).

Almost surely, 26847612314161 is an apocalyptic number.

It is an amenable number.

6847612314161 is a deficient number, since it is larger than the sum of its proper divisors (1).

6847612314161 is an equidigital number, since it uses as much as digits as its factorization.

6847612314161 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1161216, while the sum is 50.

The spelling of 6847612314161 in words is "six trillion, eight hundred forty-seven billion, six hundred twelve million, three hundred fourteen thousand, one hundred sixty-one".