Base | Representation |
---|---|
bin | 110001110111101001111… |
… | …0110110001101110010111 |
3 | 220021020102221100212110011 |
4 | 1203233103312301232113 |
5 | 1344244021430023033 |
6 | 22324410245341051 |
7 | 1305121116563161 |
oct | 143572366615627 |
9 | 26236387325404 |
10 | 6854027189143 |
11 | 220285a733a92 |
12 | 928433a07787 |
13 | 3a94414ca334 |
14 | 199a45675931 |
15 | bd450465ccd |
hex | 63bd3db1b97 |
6854027189143 has 2 divisors, whose sum is σ = 6854027189144. Its totient is φ = 6854027189142.
The previous prime is 6854027189129. The next prime is 6854027189161. The reversal of 6854027189143 is 3419817204586.
6854027189143 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-6854027189143 is a prime.
It is a super-2 number, since 2×68540271891432 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (6854027184143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3427013594571 + 3427013594572.
It is an arithmetic number, because the mean of its divisors is an integer number (3427013594572).
It is a 1-persistent number, because it is pandigital, but 2⋅6854027189143 = 13708054378286 is not.
Almost surely, 26854027189143 is an apocalyptic number.
6854027189143 is a deficient number, since it is larger than the sum of its proper divisors (1).
6854027189143 is an equidigital number, since it uses as much as digits as its factorization.
6854027189143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11612160, while the sum is 58.
The spelling of 6854027189143 in words is "six trillion, eight hundred fifty-four billion, twenty-seven million, one hundred eighty-nine thousand, one hundred forty-three".
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