Base | Representation |
---|---|
bin | 100000000110111000… |
… | …0100101100101110011 |
3 | 20120222021012001002021 |
4 | 1000031300211211303 |
5 | 2112202240124202 |
6 | 51401512332311 |
7 | 4660440012415 |
oct | 1001560454563 |
9 | 216867161067 |
10 | 68950317427 |
11 | 27272725012 |
12 | 114433a4097 |
13 | 666ab336c4 |
14 | 34a14549b5 |
15 | 1bd83b8a37 |
hex | 100dc25973 |
68950317427 has 2 divisors, whose sum is σ = 68950317428. Its totient is φ = 68950317426.
The previous prime is 68950317413. The next prime is 68950317479. The reversal of 68950317427 is 72471305986.
It is an a-pointer prime, because the next prime (68950317479) can be obtained adding 68950317427 to its sum of digits (52).
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-68950317427 is a prime.
It is not a weakly prime, because it can be changed into another prime (68950317127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 34475158713 + 34475158714.
It is an arithmetic number, because the mean of its divisors is an integer number (34475158714).
It is a 1-persistent number, because it is pandigital, but 2⋅68950317427 = 137900634854 is not.
Almost surely, 268950317427 is an apocalyptic number.
68950317427 is a deficient number, since it is larger than the sum of its proper divisors (1).
68950317427 is an equidigital number, since it uses as much as digits as its factorization.
68950317427 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2540160, while the sum is 52.
The spelling of 68950317427 in words is "sixty-eight billion, nine hundred fifty million, three hundred seventeen thousand, four hundred twenty-seven".
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