Base | Representation |
---|---|
bin | 101001001000100… |
… | …011110110011101 |
3 | 1210002120012202012 |
4 | 221020203312131 |
5 | 2403132003403 |
6 | 152251241005 |
7 | 23046560036 |
oct | 5110436635 |
9 | 1702505665 |
10 | 690109853 |
11 | 324604824 |
12 | 173149165 |
13 | acc88834 |
14 | 67921a8d |
15 | 408bbed8 |
hex | 29223d9d |
690109853 has 2 divisors, whose sum is σ = 690109854. Its totient is φ = 690109852.
The previous prime is 690109837. The next prime is 690109859. The reversal of 690109853 is 358901096.
690109853 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 590149849 + 99960004 = 24293^2 + 9998^2 .
It is a cyclic number.
It is not a de Polignac number, because 690109853 - 24 = 690109837 is a prime.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 690109853.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (690109859) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 345054926 + 345054927.
It is an arithmetic number, because the mean of its divisors is an integer number (345054927).
Almost surely, 2690109853 is an apocalyptic number.
It is an amenable number.
690109853 is a deficient number, since it is larger than the sum of its proper divisors (1).
690109853 is an equidigital number, since it uses as much as digits as its factorization.
690109853 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 58320, while the sum is 41.
The square root of 690109853 is about 26269.9420060266. The cubic root of 690109853 is about 883.7024845431.
The spelling of 690109853 in words is "six hundred ninety million, one hundred nine thousand, eight hundred fifty-three".
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