Search a number
-
+
690643134757 is a prime number
BaseRepresentation
bin10100000110011011000…
…10011110100100100101
32110000200002220101122101
422003031202132210211
542303414120303012
61245135503132101
7100616531533012
oct12031542364445
92400602811571
10690643134757
1124699a054314
12b1a26ba4031
1350186a9b9a4
14255da756709
1512e728d7d57
hexa0cd89e925

690643134757 has 2 divisors, whose sum is σ = 690643134758. Its totient is φ = 690643134756.

The previous prime is 690643134691. The next prime is 690643134773. The reversal of 690643134757 is 757431346096.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 683905844196 + 6737290561 = 826986^2 + 82081^2 .

It is a cyclic number.

It is not a de Polignac number, because 690643134757 - 223 = 690634746149 is a prime.

It is a super-2 number, since 2×6906431347572 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 690643134698 and 690643134707.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (690643134157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 345321567378 + 345321567379.

It is an arithmetic number, because the mean of its divisors is an integer number (345321567379).

Almost surely, 2690643134757 is an apocalyptic number.

It is an amenable number.

690643134757 is a deficient number, since it is larger than the sum of its proper divisors (1).

690643134757 is an equidigital number, since it uses as much as digits as its factorization.

690643134757 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11430720, while the sum is 55.

The spelling of 690643134757 in words is "six hundred ninety billion, six hundred forty-three million, one hundred thirty-four thousand, seven hundred fifty-seven".