Search a number
-
+
691204291423 is a prime number
BaseRepresentation
bin10100000111011101111…
…11000111101101011111
32110002010012211002212121
422003232333013231133
542311041244311143
61245311310443411
7100636454352202
oct12035677075537
92402105732777
10691204291423
11247157891658
12b1b62b03567
1350246117359
14256510ab939
1512ea6cd17ed
hexa0eefc7b5f

691204291423 has 2 divisors, whose sum is σ = 691204291424. Its totient is φ = 691204291422.

The previous prime is 691204291409. The next prime is 691204291471. The reversal of 691204291423 is 324192402196.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-691204291423 is a prime.

It is a super-4 number, since 4×6912042914234 (a number of 48 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 691204291423.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (691204291403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 345602145711 + 345602145712.

It is an arithmetic number, because the mean of its divisors is an integer number (345602145712).

Almost surely, 2691204291423 is an apocalyptic number.

691204291423 is a deficient number, since it is larger than the sum of its proper divisors (1).

691204291423 is an equidigital number, since it uses as much as digits as its factorization.

691204291423 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 186624, while the sum is 43.

The spelling of 691204291423 in words is "six hundred ninety-one billion, two hundred four million, two hundred ninety-one thousand, four hundred twenty-three".