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6934303235149 is a prime number
BaseRepresentation
bin110010011101000010010…
…1011100101110001001101
3220112220122111220112101021
41210322010223211301031
51402102423112011044
622425324103514141
71313662332656503
oct144720453456115
926486574815337
106934303235149
112233904443564
1293bab8158951
133b3b95893b84
1419d89cd4a673
15c059ccb0e84
hex64e84ae5c4d

6934303235149 has 2 divisors, whose sum is σ = 6934303235150. Its totient is φ = 6934303235148.

The previous prime is 6934303235099. The next prime is 6934303235177. The reversal of 6934303235149 is 9415323034396.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3702872761225 + 3231430473924 = 1924285^2 + 1797618^2 .

It is a cyclic number.

It is not a de Polignac number, because 6934303235149 - 215 = 6934303202381 is a prime.

It is a super-2 number, since 2×69343032351492 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 6934303235096 and 6934303235105.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (6934303232149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3467151617574 + 3467151617575.

It is an arithmetic number, because the mean of its divisors is an integer number (3467151617575).

Almost surely, 26934303235149 is an apocalyptic number.

It is an amenable number.

6934303235149 is a deficient number, since it is larger than the sum of its proper divisors (1).

6934303235149 is an equidigital number, since it uses as much as digits as its factorization.

6934303235149 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6298560, while the sum is 52.

The spelling of 6934303235149 in words is "six trillion, nine hundred thirty-four billion, three hundred three million, two hundred thirty-five thousand, one hundred forty-nine".