Base | Representation |
---|---|
bin | 110010011101001011100… |
… | …0100110011010010011101 |
3 | 220112221110000120222102211 |
4 | 1210322113010303102131 |
5 | 1402104041112142023 |
6 | 22425414450120421 |
7 | 1314003101011603 |
oct | 144722704632235 |
9 | 26487400528384 |
10 | 6934611834013 |
11 | 2233a52660446 |
12 | 93bb83580111 |
13 | 3b3c147b2856 |
14 | 19d8cbd1b873 |
15 | c05b9e1ca0d |
hex | 64e9713349d |
6934611834013 has 2 divisors, whose sum is σ = 6934611834014. Its totient is φ = 6934611834012.
The previous prime is 6934611833999. The next prime is 6934611834071. The reversal of 6934611834013 is 3104381164396.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3585558112249 + 3349053721764 = 1893557^2 + 1830042^2 .
It is a cyclic number.
It is not a de Polignac number, because 6934611834013 - 225 = 6934578279581 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (6934611864013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3467305917006 + 3467305917007.
It is an arithmetic number, because the mean of its divisors is an integer number (3467305917007).
Almost surely, 26934611834013 is an apocalyptic number.
It is an amenable number.
6934611834013 is a deficient number, since it is larger than the sum of its proper divisors (1).
6934611834013 is an equidigital number, since it uses as much as digits as its factorization.
6934611834013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1119744, while the sum is 49.
The spelling of 6934611834013 in words is "six trillion, nine hundred thirty-four billion, six hundred eleven million, eight hundred thirty-four thousand, thirteen".
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