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693813125497 is a prime number
BaseRepresentation
bin10100001100010100111…
…11000010000101111001
32110022212000210121102211
422012022133002011321
542331412130003442
61250422223055121
7101061223155352
oct12061237020571
92408760717384
10693813125497
11248276470278
12b25707414a1
135057076125b
142581b76cd29
15130aad59617
hexa18a7c2179

693813125497 has 2 divisors, whose sum is σ = 693813125498. Its totient is φ = 693813125496.

The previous prime is 693813125479. The next prime is 693813125503. The reversal of 693813125497 is 794521318396.

It is a happy number.

Together with previous prime (693813125479) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 642852771961 + 50960353536 = 801781^2 + 225744^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-693813125497 is a prime.

It is a super-2 number, since 2×6938131254972 (a number of 24 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (693813125437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 346906562748 + 346906562749.

It is an arithmetic number, because the mean of its divisors is an integer number (346906562749).

Almost surely, 2693813125497 is an apocalyptic number.

It is an amenable number.

693813125497 is a deficient number, since it is larger than the sum of its proper divisors (1).

693813125497 is an equidigital number, since it uses as much as digits as its factorization.

693813125497 is an evil number, because the sum of its binary digits is even.

The product of its digits is 9797760, while the sum is 58.

The spelling of 693813125497 in words is "six hundred ninety-three billion, eight hundred thirteen million, one hundred twenty-five thousand, four hundred ninety-seven".