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7051142113 is a prime number
BaseRepresentation
bin1101001000100011…
…11110001111100001
3200012101222010120121
412210101332033201
5103420043021423
63123402240241
7336506501431
oct64421761741
920171863517
107051142113
112a99205484
1214494b6081
13884aa1152
144ac6702c1
152b406c45d
hex1a447e3e1

7051142113 has 2 divisors, whose sum is σ = 7051142114. Its totient is φ = 7051142112.

The previous prime is 7051142083. The next prime is 7051142159. The reversal of 7051142113 is 3112411507.

7051142113 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5127705664 + 1923436449 = 71608^2 + 43857^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-7051142113 is a prime.

It is not a weakly prime, because it can be changed into another prime (7051148113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3525571056 + 3525571057.

It is an arithmetic number, because the mean of its divisors is an integer number (3525571057).

Almost surely, 27051142113 is an apocalyptic number.

It is an amenable number.

7051142113 is a deficient number, since it is larger than the sum of its proper divisors (1).

7051142113 is an equidigital number, since it uses as much as digits as its factorization.

7051142113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 840, while the sum is 25.

The square root of 7051142113 is about 83971.0790272460. The cubic root of 7051142113 is about 1917.5785186110.

The spelling of 7051142113 in words is "seven billion, fifty-one million, one hundred forty-two thousand, one hundred thirteen".