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71068131344173 is a prime number
BaseRepresentation
bin10000001010001011010110…
…101110010011111100101101
3100022122001021021012002021011
4100022023112232103330231
533303340013111003143
6411052125425105221
720653334355166405
oct2012132656237455
9308561237162234
1071068131344173
112070a909446327
127b79591488211
13308690823c082
141379a04659805
158339a27a1e9d
hex40a2d6b93f2d

71068131344173 has 2 divisors, whose sum is σ = 71068131344174. Its totient is φ = 71068131344172.

The previous prime is 71068131344141. The next prime is 71068131344191. The reversal of 71068131344173 is 37144313186017.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 62978873861929 + 8089257482244 = 7935923^2 + 2844162^2 .

It is a cyclic number.

It is not a de Polignac number, because 71068131344173 - 25 = 71068131344141 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (71068131344113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35534065672086 + 35534065672087.

It is an arithmetic number, because the mean of its divisors is an integer number (35534065672087).

Almost surely, 271068131344173 is an apocalyptic number.

It is an amenable number.

71068131344173 is a deficient number, since it is larger than the sum of its proper divisors (1).

71068131344173 is an equidigital number, since it uses as much as digits as its factorization.

71068131344173 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1016064, while the sum is 49.

The spelling of 71068131344173 in words is "seventy-one trillion, sixty-eight billion, one hundred thirty-one million, three hundred forty-four thousand, one hundred seventy-three".