71110669153 has 2 divisors, whose sum is σ = 71110669154. Its totient is φ = 71110669152.

The previous prime is 71110669111. The next prime is 71110669193. The reversal of 71110669153 is 35196601117.

It is an a-pointer prime, because the next prime (71110669193) can be obtained adding 71110669153 to its sum of digits (40).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 66395374929 + 4715294224 = 257673^2 + 68668^2 .

It is a cyclic number.

It is not a de Polignac number, because 71110669153 - 2¹³ = 71110660961 is a prime.

It is a super-3 number, since 3×71110669153³ (a number of 34 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (71110669193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35555334576 + 35555334577.

It is an arithmetic number, because the mean of its divisors is an integer number (35555334577).

Almost surely, 2^71110669153 is an apocalyptic number.

It is an amenable number.

71110669153 is a deficient number, since it is larger than the sum of its proper divisors (1).

71110669153 is an equidigital number, since it uses as much as digits as its factorization.

71110669153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 34020, while the sum is 40.

The spelling of 71110669153 in words is "seventy-one billion, one hundred ten million, six hundred sixty-nine thousand, one hundred fifty-three".