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71122991414413 is a prime number
BaseRepresentation
bin10000001010111110011100…
…101000110111110010001101
3100022211021212120002101220111
4100022332130220313302031
533310234341300230123
6411133241242520021
720660316013121221
oct2012763450676215
9308737776071814
1071122991414413
1120731100532054
127b88141b06011
13308bb3bb562b3
14137c52a624781
15835113b5c90d
hex40af9ca37c8d

71122991414413 has 2 divisors, whose sum is σ = 71122991414414. Its totient is φ = 71122991414412.

The previous prime is 71122991414399. The next prime is 71122991414417. The reversal of 71122991414413 is 31441419922117.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 63507941440969 + 7615049973444 = 7969187^2 + 2759538^2 .

It is an emirp because it is prime and its reverse (31441419922117) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 71122991414413 - 225 = 71122957859981 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (71122991414417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35561495707206 + 35561495707207.

It is an arithmetic number, because the mean of its divisors is an integer number (35561495707207).

Almost surely, 271122991414413 is an apocalyptic number.

It is an amenable number.

71122991414413 is a deficient number, since it is larger than the sum of its proper divisors (1).

71122991414413 is an equidigital number, since it uses as much as digits as its factorization.

71122991414413 is an evil number, because the sum of its binary digits is even.

The product of its digits is 435456, while the sum is 49.

The spelling of 71122991414413 in words is "seventy-one trillion, one hundred twenty-two billion, nine hundred ninety-one million, four hundred fourteen thousand, four hundred thirteen".