Base | Representation |
---|---|
bin | 100001001000001010… |
… | …1011001010111011011 |
3 | 20210121221100111011021 |
4 | 1002100111121113123 |
5 | 2131144044123023 |
6 | 52403130343311 |
7 | 5065640364103 |
oct | 1022025312733 |
9 | 223557314137 |
10 | 71141004763 |
11 | 28197273914 |
12 | 11954b8ab37 |
13 | 69299542ba |
14 | 362c38a203 |
15 | 1cb589635d |
hex | 10905595db |
71141004763 has 2 divisors, whose sum is σ = 71141004764. Its totient is φ = 71141004762.
The previous prime is 71141004691. The next prime is 71141004769. The reversal of 71141004763 is 36740014117.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 71141004763 - 213 = 71140996571 is a prime.
It is a super-2 number, since 2×711410047632 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (71141004769) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35570502381 + 35570502382.
It is an arithmetic number, because the mean of its divisors is an integer number (35570502382).
Almost surely, 271141004763 is an apocalyptic number.
71141004763 is a deficient number, since it is larger than the sum of its proper divisors (1).
71141004763 is an equidigital number, since it uses as much as digits as its factorization.
71141004763 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14112, while the sum is 34.
The spelling of 71141004763 in words is "seventy-one billion, one hundred forty-one million, four thousand, seven hundred sixty-three".
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