Base | Representation |
---|---|
bin | 10100101101001001100… |
… | …01101010111011001011 |
3 | 2112000100001202020221211 |
4 | 22112210301222323023 |
5 | 43124004111310024 |
6 | 1302454525313551 |
7 | 102253666654315 |
oct | 12264461527313 |
9 | 2460301666854 |
10 | 711434088139 |
11 | 254798aa5315 |
12 | b5a69a058b7 |
13 | 5211b2ac878 |
14 | 2660dad07b5 |
15 | 1378cce0594 |
hex | a5a4c6aecb |
711434088139 has 2 divisors, whose sum is σ = 711434088140. Its totient is φ = 711434088138.
The previous prime is 711434088137. The next prime is 711434088149. The reversal of 711434088139 is 931880434117.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 711434088139 - 21 = 711434088137 is a prime.
It is a super-2 number, since 2×7114340881392 (a number of 25 digits) contains 22 as substring.
Together with 711434088137, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 711434088092 and 711434088101.
It is not a weakly prime, because it can be changed into another prime (711434088137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 355717044069 + 355717044070.
It is an arithmetic number, because the mean of its divisors is an integer number (355717044070).
Almost surely, 2711434088139 is an apocalyptic number.
711434088139 is a deficient number, since it is larger than the sum of its proper divisors (1).
711434088139 is an equidigital number, since it uses as much as digits as its factorization.
711434088139 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 580608, while the sum is 49.
The spelling of 711434088139 in words is "seven hundred eleven billion, four hundred thirty-four million, eighty-eight thousand, one hundred thirty-nine".
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