Base | Representation |
---|---|
bin | 110011110011100011111… |
… | …0110111101010010001011 |
3 | 221012200020222102101221212 |
4 | 1213213013312331102023 |
5 | 1413123443123213001 |
6 | 23050533554523335 |
7 | 1333261026263636 |
oct | 147470766752213 |
9 | 27180228371855 |
10 | 7120113882251 |
11 | 22a5694735927 |
12 | 96bb1389654b |
13 | 3c85682a7136 |
14 | 1a8888744c1d |
15 | c532569c7bb |
hex | 679c7dbd48b |
7120113882251 has 2 divisors, whose sum is σ = 7120113882252. Its totient is φ = 7120113882250.
The previous prime is 7120113882227. The next prime is 7120113882253. The reversal of 7120113882251 is 1522883110217.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 7120113882251 - 214 = 7120113865867 is a prime.
Together with 7120113882253, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 7120113882199 and 7120113882208.
It is not a weakly prime, because it can be changed into another prime (7120113882253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3560056941125 + 3560056941126.
It is an arithmetic number, because the mean of its divisors is an integer number (3560056941126).
Almost surely, 27120113882251 is an apocalyptic number.
7120113882251 is a deficient number, since it is larger than the sum of its proper divisors (1).
7120113882251 is an equidigital number, since it uses as much as digits as its factorization.
7120113882251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 53760, while the sum is 41.
Adding to 7120113882251 its reverse (1522883110217), we get a palindrome (8642996992468).
The spelling of 7120113882251 in words is "seven trillion, one hundred twenty billion, one hundred thirteen million, eight hundred eighty-two thousand, two hundred fifty-one".
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