7133623900141 has 2 divisors, whose sum is σ = 7133623900142. Its totient is φ = 7133623900140.

The previous prime is 7133623900127. The next prime is 7133623900157. The reversal of 7133623900141 is 1410093263317.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6961307588041 + 172316312100 = 2638429^2 + 415110^2 .

It is an emirp because it is prime and its reverse (1410093263317) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-7133623900141 is a prime.

It is a super-3 number, since 3×7133623900141³ (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 7133623900094 and 7133623900103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (7133623900241) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3566811950070 + 3566811950071.

It is an arithmetic number, because the mean of its divisors is an integer number (3566811950071).

Almost surely, 2^{7133623900141} is an apocalyptic number.

It is an amenable number.

7133623900141 is a deficient number, since it is larger than the sum of its proper divisors (1).

7133623900141 is an equidigital number, since it uses as much as digits as its factorization.

7133623900141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 81648, while the sum is 40.

The spelling of 7133623900141 in words is "seven trillion, one hundred thirty-three billion, six hundred twenty-three million, nine hundred thousand, one hundred forty-one".