Base | Representation |
---|---|
bin | 10000001110000110101100… |
… | …100011000000011110011011 |
3 | 100100120211212100020110222101 |
4 | 100032012230203000132123 |
5 | 33322300214202134103 |
6 | 411420121114104231 |
7 | 21012000210524164 |
oct | 2016065443003633 |
9 | 310524770213871 |
10 | 71338006677403 |
11 | 20804307a9a604 |
12 | 800194a11b077 |
13 | 30a61b6c0676b |
14 | 1388ac698076b |
15 | 83a9ea40da1d |
hex | 40e1ac8c079b |
71338006677403 has 2 divisors, whose sum is σ = 71338006677404. Its totient is φ = 71338006677402.
The previous prime is 71338006677401. The next prime is 71338006677463. The reversal of 71338006677403 is 30477660083317.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 71338006677403 - 21 = 71338006677401 is a prime.
It is a super-2 number, since 2×713380066774032 (a number of 29 digits) contains 22 as substring.
Together with 71338006677401, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (71338006677401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35669003338701 + 35669003338702.
It is an arithmetic number, because the mean of its divisors is an integer number (35669003338702).
Almost surely, 271338006677403 is an apocalyptic number.
71338006677403 is a deficient number, since it is larger than the sum of its proper divisors (1).
71338006677403 is an equidigital number, since it uses as much as digits as its factorization.
71338006677403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10668672, while the sum is 55.
The spelling of 71338006677403 in words is "seventy-one trillion, three hundred thirty-eight billion, six million, six hundred seventy-seven thousand, four hundred three".
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