Base | Representation |
---|---|
bin | 110011111010111100111… |
… | …1000010100000001111111 |
3 | 221021012020002122022100002 |
4 | 1213311321320110001333 |
5 | 1413403444240441103 |
6 | 23102120530224515 |
7 | 1334362241544023 |
oct | 147657170240177 |
9 | 27235202568302 |
10 | 7135985483903 |
11 | 2301399853091 |
12 | 97300312513b |
13 | 3c9bc75858c3 |
14 | 1a9552612383 |
15 | c5953c7e488 |
hex | 67d79e1407f |
7135985483903 has 2 divisors, whose sum is σ = 7135985483904. Its totient is φ = 7135985483902.
The previous prime is 7135985483849. The next prime is 7135985483909. The reversal of 7135985483903 is 3093845895317.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 7135985483903 - 212 = 7135985479807 is a prime.
It is a super-2 number, since 2×71359854839032 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 7135985483903.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (7135985483909) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3567992741951 + 3567992741952.
It is an arithmetic number, because the mean of its divisors is an integer number (3567992741952).
Almost surely, 27135985483903 is an apocalyptic number.
7135985483903 is a deficient number, since it is larger than the sum of its proper divisors (1).
7135985483903 is an equidigital number, since it uses as much as digits as its factorization.
7135985483903 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 97977600, while the sum is 65.
The spelling of 7135985483903 in words is "seven trillion, one hundred thirty-five billion, nine hundred eighty-five million, four hundred eighty-three thousand, nine hundred three".
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