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7140959953 is a prime number
BaseRepresentation
bin1101010011010001…
…00110011011010001
3200102122222100111021
412221220212123101
5104111041204303
63140331315441
7341650105141
oct65150463321
920378870437
107140959953
1130349819a6
1214735abb81
1389a58b1ba
144ba570921
152bbdaeebd
hex1a9a266d1

7140959953 has 2 divisors, whose sum is σ = 7140959954. Its totient is φ = 7140959952.

The previous prime is 7140959923. The next prime is 7140960011. The reversal of 7140959953 is 3599590417.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5465940624 + 1675019329 = 73932^2 + 40927^2 .

It is an emirp because it is prime and its reverse (3599590417) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-7140959953 is a prime.

It is a super-3 number, since 3×71409599533 (a number of 31 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 7140959953.

It is not a weakly prime, because it can be changed into another prime (7140959923) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3570479976 + 3570479977.

It is an arithmetic number, because the mean of its divisors is an integer number (3570479977).

Almost surely, 27140959953 is an apocalyptic number.

It is an amenable number.

7140959953 is a deficient number, since it is larger than the sum of its proper divisors (1).

7140959953 is an equidigital number, since it uses as much as digits as its factorization.

7140959953 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1530900, while the sum is 52.

The square root of 7140959953 is about 84504.2008009069. The cubic root of 7140959953 is about 1925.6862637113.

The spelling of 7140959953 in words is "seven billion, one hundred forty million, nine hundred fifty-nine thousand, nine hundred fifty-three".