Base | Representation |
---|---|
bin | 10100110011100000001… |
… | …01010001011101001111 |
3 | 2112100010202222121112012 |
4 | 22121300011101131033 |
5 | 43203000310022201 |
6 | 1304221213131435 |
7 | 102434345154302 |
oct | 12316005213517 |
9 | 2470122877465 |
10 | 714845001551 |
11 | 25618940501a |
12 | b6660189b7b |
13 | 52542b56c25 |
14 | 26854adcb39 |
15 | 138dc4a15bb |
hex | a67015174f |
714845001551 has 2 divisors, whose sum is σ = 714845001552. Its totient is φ = 714845001550.
The previous prime is 714845001509. The next prime is 714845001569. The reversal of 714845001551 is 155100548417.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 714845001551 - 214 = 714844985167 is a prime.
It is a super-2 number, since 2×7148450015512 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 714845001499 and 714845001508.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (714845001571) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 357422500775 + 357422500776.
It is an arithmetic number, because the mean of its divisors is an integer number (357422500776).
Almost surely, 2714845001551 is an apocalyptic number.
714845001551 is a deficient number, since it is larger than the sum of its proper divisors (1).
714845001551 is an equidigital number, since it uses as much as digits as its factorization.
714845001551 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 112000, while the sum is 41.
Adding to 714845001551 its reverse (155100548417), we get a palindrome (869945549968).
The spelling of 714845001551 in words is "seven hundred fourteen billion, eight hundred forty-five million, one thousand, five hundred fifty-one".
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